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Q.

A container contains water to a depth of 0.5 m. When the container starts moving upwards with constant acceleration ‘a’, the hydrostatic pressure at the bottom is found to be $6 x 10^{3} N / m^{2}$ . Then the value of ‘a’ is

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a

$2 m / s^{2}$

b

$1.5 m / s^{2}$

c

$2.5 m / s^{2}$

d

$4 m / s^{2}$

answer is A.

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Detailed Solution

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Hydrostatic pressure $P = ρ (g + a) h$

$\Rightarrow a = \frac{p}{ρh} - g = (\frac{6 x 10^{3}}{10^{3} x 0.5} - 10) m / s^{2} = 2 m / s^{2}$

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A container contains water to a depth of 0.5 m. When the container starts moving upwards with constant acceleration ‘a’, the hydrostatic pressure at the bottom is found to be 6 x 103 N/m2. Then the value of ‘a’ is