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A container having a hole at the bottom is free to move on a horizontal surface. As the liquid comes out, container moves in backward direction with an acceleration $α$ . Neglect the mass of container. Select the correct option(s).

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$α$ is independent of height of liquid in vessel

$α$ is given by $α = \frac{g h}{a}$

$α$ is given by $α = \frac{a g}{A}$

$α$ is given by $α = \frac{2 a g}{A}$

answer is A, D.

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Detailed Solution

$V = \sqrt{2 g y} F = ρ_{} a_{} 2 g y$

$(ρ A y) α = ρ a 2 g y \Rightarrow α = \frac{a}{A} 2 g$

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