A container of large cross-sectional area has a small orifice at its bottom. The container is filled with water upto a height of ‘h’ above the orifice and mass flow rate of water through the orifice is 2 Kg/sec. If the height of water surface above the orifice is made 4h and cross-sectional area of the orifice is doubled, then mass flow rate of water will be

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

16 Kg

8 Kg

4 Kg

12 Kg

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

If ‘a’ be the cross sectional area of the orifice, then mass flow rate $m = ρ . a . \sqrt{2 gh}$

$\begin{array}{l} ∴ \frac{{(\overset{•}{m})}^{1}}{\overset{•}{m}} = (\frac{a^{1}}{a}) \sqrt{\frac{h^{1}}{h}} \Rightarrow \frac{{(\overset{•}{m})}^{1}}{2} = (2) \sqrt{4} \\ \Rightarrow {(\overset{•}{m})}^{1} = 8 Kg \end{array}$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th