A container of volume 200 cm³ contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature 200 K (R = 8.3 JK^-1 mol^-1) will be :-

Pressure of a gas is given by _____

$\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{v}}$

n = total no. of moles, T is absolute temperature and V is the volume of the gas. Here,

$P=\frac{(n_1+n_2)RT}{V}$

n₁ = no. of moles of hydrogen = 0.2

n₂ = no.of moles of argon = 0.3

$P=\frac{\left(0.5\right)8.3\times 200}{200\times {10}^{-6}}$

$=4.15\times {10}^6\mathrm{Pa}.$