A container when is empty weighs 50 gm. After certain liquid of density 25 gm/dm3 is filled, its mass becomes equal to 100 gm. The volume of the container will be :

W(gas)= W(gas+vessel)-W(vessel) =100-50 =50 gr d=W(gas)V(gas); V=5025=2 dm3

W(gas)= W(gas+vessel)-W(vessel) =100-50 =50 gr d=W(gas)V(gas); V=5025=2 dm3

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A container when is empty weighs 50 gm. After certain liquid of density 25 gm/dm³ is filled, its mass becomes equal to 100 gm. The volume of the container will be :

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0.5 dm³

1 dm³

2 dm³

0.25 dm³

answer is D.

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$W_{(gas)} = W_{(gas + vessel)} - W_{(vessel)} = 100 - 50 = 50 gr d = \frac{W_{(gas)}}{V_{(gas)}}; V = \frac{50}{25} = 2 {dm}^{3}$

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