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Q.

A container with a volume of  20.0 L holds N2(g) and H2O(l) at 300 K and 1.0 atm. The liquid water is then decomposed completely into  H2(g) and O2(g) by any means, at constant temperature. If the final pressure becomes 1.86 atm, what was the mass of water (in gm) present initially. Neglect the initial volume of water. [Given : Vapour pressure of water at  300 K=0.04 atm,R=0.08 L-atm/K-mol]

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answer is 9.

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Detailed Solution

Here, 

nN2=(10.04)×200.08×300=0.05 moles; PN2=10.04=0.96atmnH2+O2=0.90×200.08×300=0.75H2OH2+12O2a moles 

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