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Q.

A continuous and differentiable function y = f(x) is such that its graph cuts line y = mx + c  at n distinct points. Then the minimum number of points at which f''x=0 is/are

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a

n-3

b

cannot say

c

n-1

d

n-2

answer is C.

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Detailed Solution

From LMVT, there exists at least (n - 1) points where f '(x) = m.

Therefore, there exist at least (n -2) points where f"(x) = 0   (using Rolle's theorem).

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