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A converging beam of rays is incident on a diverging lens. Having passed through the lens the rays intersect at a point 15 cm from the lens. If the lens is removed the point where the rays meet will move 5 cm closer to the mounting that holds the lens. Find focal length (magnitude, in cm ) of the lens.

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detailed solution

Correct option is ^

 For concave lens, u=+10cm (virtual object)                       and  v=+15cm We have 1+151+10=1f                            f=30cm.

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detailed solution

Correct answer is 30

 For concave lens, u=+10cm (virtual object)                       and  v=+15cm We have 1+151+10=1f                            f=30cm.

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