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A converging lens of 2.5cm focal length is used as a simple microscope producing virtual image at 25cm from the eye. The position of the object from the lens is (nearly)

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2cm

2.2cm

4cm

1cm

answer is C.

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Detailed Solution

$\begin{array}{l} f = 2 .5 cm, V_{e} = - 2 .5 cm; \frac{1}{f} = \frac{1}{v_{e}} - \frac{1}{u_{e}} \\ u_{e} = 2 .2 cm \end{array}$

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