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Q.

A converging lens of power $P_{1} = + 5 D$ and a concave mirror of power $P_{2} = + 16 D$ are placed at a separation 80cm such that their principal axis coincide. A point object is placed left side of the lens on its principal axes at a distance $X_{1}$ from the lens such that image of the object coincides with the object itself.
The value of $X_{1} (i n c m) i s \dots \dots \dots ..$

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answer is 26.67.

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Detailed Solution

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$\frac{1}{80} - \frac{1}{- x_{1}} = \frac{1}{20}$

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$\frac{1}{x_{1}} = \frac{1}{20} - \frac{1}{80} \Rightarrow x_{1} = 26.67 cm$

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A converging lens of power P1=+5D and a concave mirror of power P2=+16D are placed at a separation 80cm such that their principal axis coincide. A point object is placed left side of the lens on its principal axes at a distance X1 from the lens such that image of the object coincides with the object itself.The value of X1(in cm)is………..