A convex lens has a 10 cm focal length. Which of the following statements regarding the nature and position of the image is correct if an object is placed 9.8 cm in front of the convex lens?

f = 10 cm (Focal length of a convex lens is always positive.)
u = -9.8 cm (Object distance is always taken as negative.)

Lens equation: $\frac{1}{\mathrm{f}}=\frac{1}{\mathrm{v}}-\frac{1}{\mathrm{u}}$

Where u is the object distance, v is the image distance, and f is the focal length.

Putting the given values in the equation, 

$\Rightarrow \frac{1}{10}=\frac{1}{\mathrm{v}}+\frac{1}{9.8}$

$\frac{1}{\mathrm{v}}=\frac{1}{10}-\frac{1}{9.8}=\frac{9.8-10}{98}$

$\frac{1}{\mathrm{v}}=\frac{-0.2}{98}\Rightarrow \mathrm{v}=\frac{-980}{2}$

$\mathrm{v}=-490 \mathrm{cm}$

Since the image distance is negative, it must be virtual and must be located on the side of the object.