A convex lens has a focal length of 10 cm. the location and nature of the image if a point object is placed on the principal axis at a distance of 9.8 cm is

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490 cm on the side of the object, real

510 cm on the side of the object, virtual

490 cm on the side of the object, virtual

510 cm on the side of the object, real

answer is C.

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Detailed Solution

$f = 10 cm, u = 9.8 cm$

$v = + ve, u = - ve$

We know

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{10} = \frac{1}{v} + \frac{1}{9.8}$

$\frac{1}{v} = \frac{1}{10} - \frac{1}{9.8} = \frac{9.8 - 10}{98}$

$\frac{1}{v} = \frac{- 0.2}{98} \Rightarrow v = \frac{- 980}{2}$

$v = - 490$

$v = - ve, so image virtual and same side of the object$

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