A convex lens has power P. It is cut into two halves along its principal axis. Further one piece(out of the two halves) is cut into two halves perpendicular to the principal axis(as shown in figure). Choose the incorrect option for the reported pieces

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Power of $L_{1} = \frac{P}{2}$

Power of $L_{1} = P$

Power of $L_{3} = \frac{P}{2}$

Power of $L_{2} = \frac{P}{2}$

answer is A.

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Detailed Solution

If lens cut into two halves parallel to principal axis there is no change in power but when cut perpendicular to principal axis power is halved.

Therefore,

Power of $L_{1} = P$

and

Power of $L_{2} = L_{3} = \frac{P}{2}$

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