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Q.

A convex lens immersed in water of refractive index 4/3 has a focal length of 40 cm and the same lens when immersed in a liquid of refractive index 2 has a focal length of -20 cm. The refractive index of the material of the lens is

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a

9/8

b

3/2

c

6/5

d

16/7 

answer is B.

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Detailed Solution

140=μgμw-11R1+1R2

140=μg4/3−11R1+1R2…... (i)

1−20=μg2−11R1+1R2…...(ii)

 (i) and (ii) μg=32

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