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Q.

A convex lens of focal length 0.5 m and concave lens of focal length 1 m are combined. The power of the resulting lens will be

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a

– 1 D

b

0.5 D

c

– 0.5 D

d

1 D

answer is A.

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Detailed Solution

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$P = P_{1} + P_{2} = \frac{1}{f_{1}} + \frac{1}{f_{2}} = \frac{1}{(0 .5)} + \frac{1}{(- 1)} = 1 D$

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