A convex mirror and a concave mirror of radius 10 cm each are placed 15 cm apart facing each other. An object is placed midway between them. If the reflection first takes place in the concave mirror and then in convex mirror, the position of the final image is

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on the pole of the convex mirror

on the pole of the concave mirror

at a distance of 10 cm from the convex mirror

at a distance of 5 cm from the concave mirror

answer is A.

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Detailed Solution

For a concave mirror, $u = - \frac{15}{2} cm, v = ?$

$f = - \frac{10}{2} cm = - 5 cm$

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{- 5} - \frac{1}{- 15 / 2} = - \frac{1}{5} + \frac{2}{15} = \frac{- 1}{15}$

or $v = - 15 cm$

Clearly, the position of the final image is on the pole of the convex mirror.

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