A convex mirror has a radius of curvature of 30cm. Find the position of the image of an object placed at a distance of 18cm from the mirror

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$\frac{50}{11} cm$

90 cm

$\frac{90}{11} cm$

$\frac{60}{11} cm$

answer is C.

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Detailed Solution

Given, R = 30 cm

$\Rightarrow$ f = R/2 = 30/2 = 15 cm

And u = 18 cm

From the mirror formula,

$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} \Rightarrow \frac{1}{v} = \frac{1}{15} - \frac{- 1}{18} \Rightarrow \frac{1}{v} = \frac{6 + 5}{90} = \frac{11}{90} ∴ v = \frac{90}{11} cm$

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