A convex mirror of focal length f produces an image 1nth of the size of the object. The distance of the object from the mirror is

Let, u=-xThen, v=+xn1+xn+1-x=1+fSolving, we get x=n-1f

A convex mirror of focal length f produces an image 1nth of the size of the object. The distance of the object from the mirror is

Let, u=-xThen, v=+xn1+xn+1-x=1+fSolving, we get x=n-1f

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A convex mirror of focal length $f$ produces an image ${(\frac{1}{n})}^{t h}$ of the size of the object. The distance of the object from the mirror is

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$n f$

$\frac{f}{n}$

$(n + 1) f$

$(n - 1) f$

answer is D.

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Detailed Solution

Let, $u = - x$

Then, $v = + \frac{x}{n}$

$\frac{1}{(+ \frac{x}{n})} + \frac{1}{- x} = \frac{1}{+ f}$

Solving, we get $x = (n - 1) f$

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A convex mirror of focal length f produces an image 1nth of the size of the object. The distance of the object from the mirror is

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A convex mirror of focal length $f$ produces an image ${(\frac{1}{n})}^{t h}$ of the size of the object. The distance of the object from the mirror is