A copper block of mass $5.0 kg$ is heated to a temperature of $500 ° C$ and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper: $0.39 {Jg}^{- 1} {{}^{\circ}C}^{- 1}$ and latent heat of fusion of water : $335 J g^{- 1}$ ]

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1.5 kg

5.8 kg

2.9 kg

3.8 kg

answer is C.

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Detailed Solution

Heat given by block to get 0ºC temperature

$\begin{aligned} {ΔQ}_{1} = 5 \times (0.39 \times 10^{3}) \times (500 - 0) \\ = 975 \times 10^{3} J \end{aligned}$

Heat absorbed by ice to melt m mass

$\begin{aligned} {ΔQ}_{2} = m \times (335 \times 10^{3}) J \\ {ΔQ}_{1} = {ΔQ}_{2} \\ m \times (335 \times 10^{3}) = 975 \times 10^{3} \\ m = \frac{975}{335} = 2.910 kg \end{aligned}$

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