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Q.

A copper calorimeter of a mass 300g contains 500g of water at a temperature of 20°C. A 500 g of copper block at 100°C is dropped into the calorimeter. If the resultant temperature is 25°C , then find the specific heat of copper in Jkg-1K-1 (nearly)

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a

390

b

190

c

490

d

290

answer is B.

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Detailed Solution

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Heat lost by copper block = heat gained by water + Heat gained by calorimeter
mcscth−tr=mwswtr−tc+mcsctr−tc500×sc(100−25)=500×1×(25−20)+300×sc(25−20)∴sc=0.0694cal/gm∘C∴sc=0.0694×4200≃292 J/kg⋅K

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