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Q.

A copper disc of radius 0.1 m is rotated about its natural axis with 10 rps in a uniform magnetic field of 0.1 T with its plane perpendicular to the field. The emf induced across the radius of the disc is

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a

$π \times 10 V$

b

$2 π \times 10 V$

c

$π \times 10^{- 2} V$

d

$2 π \times 10^{- 2} V$

answer is C.

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Detailed Solution

$e = \frac{1}{2} R^{2} Bω$

here $B = 0.1 T, R = 0.1 m, ω = 10 rev / s = 20 πrad / s$

$\Rightarrow e = \frac{1}{2} \times 0.01 \times 0.1 \times 20 π = π \times 10^{- 2} V$

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A copper disc of radius 0.1 m is rotated about its natural axis with 10 rps in a uniform magnetic field of 0.1 T with its plane perpendicular to the field. The emf induced across the radius of the disc is