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Q.

A copper disc of radius 0.1 m is rotated about its natural axis with 10 rps in a uniform magnetic field of 0.1 T with its plane perpendicular to the field. The emf induced across the radius of the disc is

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a

π×10V

b

2π×10V

c

π×10−2V

d

2π×10−2V

answer is C.

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Detailed Solution

e=12R2Bω

here B=0.1 T,  R=0.1 m,  ω=10rev/s=20πrad/s

⇒e=12×0.01×0.1×20π=π×10-2 V

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