A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

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$\frac{\pi }{{10}}V$

10 $\pi$ mV

$\frac{{2\pi }}{{10}}V$

20 $\pi$ mV

answer is C.

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Detailed Solution

The induced emf between centre and rim of the rotating disc is
$E = \frac{1}{2}B\omega {R^2} = \frac{1}{2} \times 0.1 \times 2\pi \times 10 \times {(0.1)^2} = 10\pi \times {10^{ - 3}}volt$

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