A copper plate of 20cm × 10cm is to be plated with silver of 1 mm thickness. The number of silver atoms required for the plating is (density of silver = 10.8 g/c.c)

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$1.2 \times 10^{24}$

$1.2 \times 10^{13}$

$2.4 \times 10^{24}$

$2.4 \times 10^{23}$

answer is A.

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Detailed Solution

Volume of copper plate $= 20 \times 10 \times 0.1 c m^{3} = 20 c m^{3}$

$d = \frac{m}{v}$

$∴$ mass of copper = d × V

$= 10.8 \times 20$

= 216 gms

Number of silver atoms $= \frac{216 \times 6 \times 10^{23}}{108} = 1.2 \times 10^{24} a t o m$

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