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A Copper plate of $20 c m \times 10 c m$ is to be plated with Ag of 1mm thickness. The number of silver atoms required for plating (density of Ag is 10.8 gm/cc)is $x \times 10^{23} .$ Here ‘x’ is ____.

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answer is 12.

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Detailed Solution

V=Area $\times$ thickness $= 20 \times 10 \times 0.1 = 20 c c$
$V o l \times d e n s i t y = m a s s = 20 \times 10.8 = 2 \times 108 g m s$
$108 g m A g \to 6 \times 10^{23} a t o m s o f A g$
$2 \times 108 g m A g \to ? 12 \times 10^{23} a t o m s$

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