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A copper rod AB of length $l$ is rotated about end A with a constant angular velocity $ω$ . Find electric field at a distance $x$ form the axis of rotation

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$\frac{m ω^{2} x}{e}$

$\frac{m ω x}{e l}$

$\frac{m e}{ω^{2} x}$

$\frac{m x}{ω^{2} l}$

answer is A.

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Detailed Solution

When rod rotates, electron in it also rotates which produce electric field E at distance $x$ . Force in electron, $F_{e} = e E = m ω^{2} x$

$∴$ $E = \frac{m ω^{2} x}{e}$

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