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A copper sphere attached to the bottom of a vertical spring is oscillating with time period 10 s. If the copper sphere is immersed in a fluid (assume the viscosity of the fluid is negligible) of specific gravity $\frac{1}{4}$ of that of the copper, then time period of the oscillation is

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10 s

20 s

2.5 s

5 s

answer is B.

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Detailed Solution

Given, time period, $T = 2 π \sqrt{\frac{m}{k}} = 10 s$

When the spring system is immersed in liquid with specific gravity $\frac{1}{4}$ th of the copper, but as the liquid is non-viscous in nature, so the time period would not be changed because there will be no change in m and k.

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