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Q.

A copper sulphate solution is diluted by 100 times. Oxidation potential of copper electrode in contact with this solution,

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An Intiative by Sri Chaitanya

a

Decreases by 0.0591 V

b

Increases by 0.0591 V

c

Decreases by 0.0295 V

d

Increases by 0.0295 V

answer is D.

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Detailed Solution

$E_{1} = E^{0} + \frac{0.0591}{2} log 100$

$E_{1} = E^{0} + 0.0591$

$E_{2} = E^{0} + \frac{0.0591}{2} log 1 = E^{0}$

R.P decreases by 0.0591 V
$∴$ O.P increases by 0.0591 V

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