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Q.

A copper wire has diameter 0.5 mm and resistivity ρ = 1.6×10-8 ohm. What will be the length of its wire to make its resistance 10 ohm. In what ratio will the resistance change if diameter gets doubled?


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a

100 m, 1:4

b

122.66 m, 1:2

c

122.66 m, 1:4

d

None of these  

answer is C.

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Detailed Solution

A copper wire has diameter 0.5 mm and resistivity ρ = 1.6×10-8 ohm. The length of its wire should be 122.66 m to make its resistance 10 ohm. If diameter gets doubled, the resistance becomes 1:4.
Radius=diameter 2
=0.52
=0.25 mm
=0.25×10-3m
Resistivity ρ = 1.6×10-8 ohm-1 and R=10 ohm
We know that, resistance R = ρlA 10=1.6×10-8×lπ(0.25×10-3)2  Length l=122.66 m
As we know, diameter d=2r. So, r=d/2. Then, A=πd2/4
If we double the diameter, then resistance will become one fourth.
Substituting this in the resistance formula, we get the ratio of resistances as 1:4.
 
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