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Q.

A copper wire of length 10 m and radius $(10^{- 2} / \sqrt{π}) m$ has electrical resistance of 10 $Ω$ . The current density in the wire for an electric field strength of 10 (V/m) is:

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a

$10^{5} A / m^{2}$

b

$10^{4} A / m^{2}$

c

$10^{6} A / m^{2}$

d

$10^{- 5} A / m^{2}$

answer is C.

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Detailed Solution

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$J= \frac{EI}{RA} = 10^{5} A / m^{2}$

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A copper wire of length 10 m and radius 10−2/πm has electrical resistance of 10Ω. The current density in the wire for an electric field strength of 10 (V/m) is: