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A copper wire of length 1m and radius 1mm is connected in series with another wire of iron of length 2 m and radius 3mm. A steady current is passed through this combination. The ratio of current densities in copper and iron wires will be

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18:1

2:3

6:1

9:1

answer is B.

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Detailed Solution

$J_{1} A_{1} = J_{2} A_{2}$
$\frac{J_{1}}{J_{2}} = \frac{A_{2}}{A_{1}} = \frac{9}{1}$

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