A copper wire of length 50 cm and area of cross section 10-6 m2 carries a current of 0.5 A. If the resistivity of copper is 1.8 x 10-8 Ωm, the electric field across the wire is

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A copper wire of length 50 cm and area of cross section 10^-6m² carries a current of 0.5 A. If the resistivity of copper is 1.8 x 10^-8 Ωm, the electric field across the wire is

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0.009 Vm^-1

0.09 vm^-1

9 vm^-1

0.9 vm^-1

answer is D.

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Detailed Solution

Potential difference across a wire of length l is

V=IR= $\frac{I ρ l}{A}$

$∴ Electric field E = \frac{V}{l} = \frac{Iρ}{A} = \frac{0.5 X 1.8 X 10^{- 8}}{10^{- 6}} = 0.009 {Vm}^{- 1}$

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