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Q.

A copper wire of $2 m m$ diameter is stretched by applying a force on $314 N$ . Find the stress in the wire

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a

$1.373 \times 10^{6} N / m^{2}$

b

$1.473 \times 10^{7} N / m^{2}$

c

$1 \times 10^{8} N / m^{2}$

d

$1.573 \times 10^{10} N / m^{2}$

answer is A.

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Detailed Solution

Stress = $\frac{F}{A} = \frac{F}{π R^{2}} = \frac{314}{3.14 \times {(1 \times 10^{- 3})}^{2}} = 10^{8} N / m^{2}$

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