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Q.

A covered wooden box has the inner measures as 115 cm, 75 cm and 35 cm and thickness of wood as 2.5 cm. The volume of the wood is

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a

85,000

c m^{3}

b

80,000

c m^{3}

c

82,125

c m^{3}

d

84,000

c m^{3}

answer is C.

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Detailed Solution

Given, the inner measure of a wooden box as 115 cm, 75 cm and 35 cm.
Since the thickness of the box is 2.5 cm, then outer measures will be (115+5) cm, (75+5) cm and (35+5) cm i.e., 120 cm, 80 cm and 40 cm.
The formula for the volume of cuboid having length, breadth and height as

l, b

and

h

respectively is given by,
Volume of a cuboid

= l \times b \times h

So, after substituting the value of all the dimensions in the formula we get,
Outer volume =

120 \times 80 \times 40

= 38400

c m^{3}

And the inner volume =

115 \times 75 \times 35

= 301875

c m^{3}

Therefore, volume of the wood = outer volume - inner volume
= 34800-301875
=82125

c m^{3}

Hence, option (3) is correct.

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