A cricket team of 11 is to be selected out of 15 players of whose 4 are bowlers. The probability that exactly 3 bowlers are included in the team is

$n\left(S\right)={15}_{c_{{ }_{11}}}$ 

$$\begin{gathered} we have to select 3 bowlers from 4 in C\left(4,3\right) ways and the remaining 8 members \\ from the remaining 11 players in C\left(11,8 \right)ways. \end{gathered}$$

$$\begin{gathered} n\left(E\right)=4_{c_{{ }_3}}{.11}_{c_{{ }_8}} \\ P\left(E\right)=\frac{4_{c_{{ }_3}}{.11}_{c_{{ }_8}}}{{15}_{c_{{ }_{11}}}}=\frac{4_{c_{{ }_3}}{.11}_{c_{{ }_8}}}{{15}_{c_4}} \end{gathered}$$