A cricket ball is thrown up at a speed of 19.6 m/s. The maximum height it can reach is ________________.

Choose the correct option.

Given,
The initial velocity (u)=19.6 m/s
The final velocity (v) =0 m/s
Acceleration due to gravity (g)=9.8m/s²
We can use a third equation of motion formula to solve this problem. 
v²−u² = 2 as
$\Rightarrow$2gh = v²−u² 
$\Rightarrow -2\times 9.8\times \mathrm{ℎ}=0^2-19.6\times 19.6$
$\Rightarrow \mathrm{h}= 19.6$ m

Therefore, the ball will be able to reach the maximum height of 19.6 m.