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A cricket ball of mass $100 g$ moving with a speed of $30 m / s$ is brought to rest by a player in $0.03 s .$ What will be the average force applied by the player?

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- 200 N

- 100 N

- 400 N

- 300 N

answer is A.

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Detailed Solution

The average resistive force applied by the player is

100 N .

Given that,
Mass

(m) = 100 g = 0.1 kg

Initial velocity

u = 30 m / s

Because the ball is at rest, so final velocity will be (v) = 0
Time,

(t) = 0.03

seconds
Form the equation

u = v + at

= > a = \frac{v - u}{t}

= > a = \frac{0 - 30}{0.03} = - 1000

Here negative sign indicates retardation
Now from the relationship of force, mass and acceleration

F = ma

F = 0.1 \times - 1000

= - 100 N

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