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Q.

A cricket ball of mass 150 g, is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of 20 m/s. If duration of contact between the ball and the bat is 0.01sec. The impulse of the force is

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a

4.8NS

b

7.4NS

c

1.2NS

d

4.7NS

answer is B.

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Detailed Solution

Mass = 150 g $= 150 \times 10^{- 3} kg$
Initial velocity = 12 m/s
Final velocity = 20 m/s
Time = 0.01 s
Impulse $= m (v - u)$
$\begin{array}{l} = 150 \times 10^{- 3} (20 + 12) \\ = 150 \times 32 \times 10^{- 3} Ns \\ J = 4800 \times 10^{- 3} Ns \\ = 4 .8 Ns \end{array}$

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