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A cricketer of height 2.5 m throws a ball at an angle of 30⁰ with the horizontal such that it is received by another cricketer of same height standing at distance of 50 m from the first one. Find the maximum height attained by the ball.

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10 m

9 m

10.7 m

9.7 m

answer is D.

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Detailed Solution

$\tan θ = \frac{4 H}{R}, H_{\max} = H + h_{crictter}, R = 50 m$

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