A cube has a side of length $1.2\times {10}^{-2}\mathrm{m}.$Its volume up to correct significant figures is

Here

Length of the cube,  $\mathrm{L}=1.2\times {10}^{-2}\mathrm{m}$

Volume of the cube, $\mathrm{V}\mathrm{\hspace{0.17em}}=\mathrm{\hspace{0.17em}}{(1.2\times \mathrm{\hspace{0.17em}}{10}^{-2}\mathrm{m})}^3$

                                              = $1.728\times {10}^{-6}{\mathrm{m}}^3$

As the result can have only two significant figures  therefore, on rounding off, we get

$\mathrm{V}=1.7\times {10}^{-6}{\mathrm{m}}^3$