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A cube has side of length 50 cm. A point charge of +35.4 $μ C$ is kept at the mid point of one edge. The total electric flux over the entire surface of the cube is

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$10^{8} V - m$

$4 \times 10^{12} V - m$

$10^{6} V - m$

$10^{12} V - m$

answer is C.

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Detailed Solution

$Q_{n e t} = \frac{35.4}{4} μ C = 8.85 μ C$

By Gauss's law, $ϕ_{E} = \frac{Q_{n e t}}{\in_{0}} = \frac{8.85 \times 10^{- 6}}{8.85 \times 10^{- 12}}$ volt-metre

$= 10^{6} V - m$

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