A cube is arranged such that its length, breadth and height are along X,Y and Z directions. One of its corners is situated at the origin. Length of each side of the cube is 25 cm. The components of electric field are $E_{x} = 400 \sqrt{2} N / C, E_{y} = 0 and E_{z} = 0$ respectively. Find the flux coming out of the cube at one end.

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zero

$25 \sqrt{2}$

$\frac{25}{\sqrt{2}}$

answer is C.

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Detailed Solution

Flux through one face = E₀L²
$= 400 \sqrt{2} \times {(25 \times 10^{- 2})}^{2} = 25 \sqrt{2}$

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