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A cube of 10N rests on a rough inclined plane of slope 3 in 5.The minimum force necessary to start the cube moving up the plane is : (the coefficient of friction is 0.6)

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1.2 N

4.8 N

10.8 N

14.8 N

answer is B.

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Detailed Solution

When the cube is to be moved up, the minimum force needed is given by :

$F = m g \sin θ + μ R = m g \sin θ + μ m g \cos θ$

$= 10 \sin θ + 0.6 \times 10 \cos θ = 10 \times \frac{3}{5} + 0.6 \times 10 \times \frac{4}{5} = 10.8 N$

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