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A cube of mass 2kg is held stationary against a rough wall by a force F = 40N passing through center C. Find perpendicular distance of normal reaction between wall and cube from point C. side of the cube is 20cm. (Take, $g = 10 m / s^{2}$ )

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8 cm

7 cm

10 cm

5 cm

answer is A.

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Detailed Solution

N=F=40N

Net moment about C=0

$∴$ Anti-clockwise moment of f= clockwise moment of N $∴$

$∴ (20) (\frac{20}{2}) = (40) \cdot x or x = 5 cm$

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