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A cube with a mass m = 20 g wettable by water floats on the surface of water. Each side of the cube has length l = 3 cm. The angle of contact between water and glass is zero degree and the surface tension of the water is 7.5 × $10^{- 2}$ N/m. The distance between the lower face of the cube and the surface of the water is

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2.434 cm

2.322 cm

2.222 cm

20/22 cm

answer is C.

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Detailed Solution

$F_{Uptthrust} = F_{Surface tension} + Weight$
$l^{2} x ρ g = 4 lT + mg$

${(. 03)}^{2} \times 10^{3} \times 10 x = . 009 + . 2$

$9 x = . 209$

$x = . 02322 m = 2.322 cm$

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