A cubic solid is made up of two elements X and Y. Atoms of X are present on every alternate corner and one at the center of cube. Y is at $\frac{1}{3} rd$ of the total faces. The empirical formula of the compound is

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$X_{2} Y_{1.5}$

$X_{2.5} Y$

${XY}_{2.5}$

$X_{1.5} Y_{2}$

answer is B.

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Detailed Solution

$\begin{array}{l} X = 4 \times \frac{1}{8} + 1 \times 1 = \frac{3}{2} \\ Y = \frac{1}{3} \times 6 \times \frac{1}{2} = 1 \end{array}$
Correct Answer $X_{1.5} Y$ (or) $X_{3} Y_{2}$

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