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A cubical block of copper of side 10 cm is floating in a vessel containing mercury. Water is poured into the vessel so that the copper block just gets submerged. The height of water column is
( $ρ_{Hg} = 13.6 g / cc, ρ_{Cu} = 7.3 g / cc, ρ_{water} = 1 gm / cc$ )

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1.25 cm

2.5 cm

5 cm

7.5 cm

answer is C.

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Detailed Solution

Let h = height of water column

then $ρ_{w} gh + ρ_{Hg} g (10 - h) = ρ_{Cu} g 10$

$\Rightarrow h + 13.6 (10 - h) = 73$

$\Rightarrow 63 = 12.6 h \Rightarrow h = 5 cm$

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