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A cubical block of side $L$ rests on a rough horizontal surface with coefficient of friction $μ$ . A horizontal force $F$ is applied on the block as shown. If the friction is sufficiently high so that the block does not slide before toppling, the minimum force F required to topple the block is:

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$Mg (1 - μ)$

$\frac{Mg}{2}$

Infinitesimal

$\frac{Mg}{4}$

answer is C.

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Detailed Solution

Toppling begins when $FL = Mg (\frac{L}{2})$

$\Rightarrow F = \frac{Mg}{2}$

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