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A cubical block of wood 10 cm on a side, floats at the interface of oil and water as shown in figure. The density of oil is $0.6 g {cm}^{- 3}$ and density of water is $1 g {cm}^{- 3} .$ Find the mass (in gm) of the block.

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answer is 760.

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Detailed Solution

As, weight = Buoyant force

$mg = [100 \times 6 \times 0.6 g] + (100 \times 1 \times 4) g$

$∴ m = 760 gm$

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