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Q.

A cubical block of wood of side 10cm floats at the interface between an oil and water with its lower surface 2cm below the interface. The heights of the oil and water columns are 10 cm each. Density of oil is 0.8g/c.c. The mass of the block is in gram is

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answer is 840.

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Detailed Solution

As the box is in equilibrium, thus the weight of the box is balanced by the total buoyancy force.

$M g = ρ_{w} x L^{2} g + ρ_{o} (L - x) L^{2} g$

$\Rightarrow M = 1 (2 \times 10 \times 10) + 0.8 (8 \times 10 \times 10) = 200 + 640 = 840 g m$

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A cubical block of wood of side 10cm floats at the interface between an oil and water with its lower surface 2cm below the interface. The heights of the oil and water columns are 10 cm each. Density of oil is 0.8g/c.c. The mass of the block is in gram is